ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 18:17Z
∑_{k=1}^{n} k = n(n+1)/2
\lim_{t\to 0} \frac{\sin t}{t} = 1
∫₀^∞ e^(-β²) dβ = √π / 2
453K
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
177K
5ψ² + 2ψ + 5 = 0
det| 9 5 ; 4 10 | = 70
45K
\frac{5}{4} \sum_{i=1}^{n} i^{2}
207K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{z\to 0} \frac{\sin z}{z} = 1
364K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
238K
det| 1 4 ; 4 2 | = -14
267K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
336K