ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:26Z
N₂ + 3H₂ ⇌ 2NH₃
det| 3 7 ; 2 4 | = -2
312K
12φ² + 6φ + 4 = 0
∫₀^∞ e^(-β²) dβ = √π / 2
125K
2H₂ + O₂ → 2H₂O
5φ² + 5φ + 0 = 0
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 4 8 ; 0 5 | = 20
68K
ΔS ≥ 0