ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:37Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-r²) dr = √π / 2
\frac{4}{6} \sum_{i=1}^{n} i^{2}
125K
12γ² + 2γ + 2 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
E = mc²
λ = h/p
det| 3 6 ; 0 4 | = 12
39K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t