ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:57Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 5 6 ; 1 6 | = 24
312K
4β² + 5β + 0 = 0
det| 7 4 ; 4 8 | = 40
125K
det| 12 1 ; 5 13 | = 151
91K
d/dφ [φ^6] = 6φ^5
6n² + 3n + 0 = 0
det| 10 9 ; 0 11 | = 110
311K
det| 5 9 ; 7 6 | = -33
68K
∫₀^∞ e^(-x²) dx = √π / 2
39K