ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:56Z
∑_{k=1}^{n} k = n(n+1)/2
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
det| 7 4 ; 4 8 | = 40
17K
CH₄ + 2O₂ → CO₂ + 2H₂O
310K
6n² + 3n + 0 = 0
∫₀^∞ e^(-β²) dβ = √π / 2
311K
det| 1 4 ; 3 2 | = -10
264K
10β² + 6β + 6 = 0
det| 1 8 ; 4 2 | = -30
68K
F = ma
d/dα [α^1] = 1α^0