ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:21Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
312K
∫₀^∞ e^(-r²) dr = √π / 2
\lim_{x\to 0} \frac{\sin x}{x} = 1
125K
12γ² + 2γ + 2 = 0
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
311K
λ = h/p
det| 3 7 ; 2 4 | = -2
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
det| 4 6 ; 0 5 | = 20
364K
det| 9 4 ; 1 10 | = 86
6K