ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:41Z
7φ² + 7φ + 6 = 0
det| 9 4 ; 1 10 | = 86
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 2 7 ; 7 3 | = -43
125K
∫₀^∞ e^(-x²) dx = √π / 2
91K
9n² + 8n + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
310K
ΔS ≥ 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
E = mc²
det| 9 8 ; 3 10 | = 66
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃