ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:21Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 4 8 ; 0 5 | = 20
302K
∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
E = mc²
∫₀^∞ e^(-x²) dx = √π / 2
311K
λ = h/p
\lim_{α\to 0} \frac{\sin α}{α} = 1
68K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O