ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:57Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 2 ; 3 6 | = 24
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∇²ω = 0
\frac{4}{6} \sum_{i=1}^{n} i^{2}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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det| 1 2 ; 7 2 | = -12
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
2H₂ + O₂ → 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
364K