ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:22Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{x\to 0} \frac{\sin x}{x} = 1
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∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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λ = h/p
det| 9 4 ; 1 10 | = 86
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
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