ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:35Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 9 4 ; 1 10 | = 86
312K
∫₀^∞ e^(-r²) dr = √π / 2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
91K
12γ² + 2γ + 2 = 0
E = mc²
∫₀^∞ e^(-β²) dβ = √π / 2
311K
λ = h/p
det| 1 8 ; 4 2 | = -30
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}