ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:49Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 6 ; 4 6 | = 6
302K
∇²ω = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
125K
∫₀^∞ e^(-n²) dn = √π / 2
91K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\frac{11}{6} \sum_{i=1}^{n} i^{2}
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Fe₂O₃ + 3CO → 2Fe + 3CO₂
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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2H₂ + O₂ → 2H₂O
det| 6 6 ; 3 7 | = 24
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10r² + 7r + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
364K
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
λ = h/p