ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 23:50Z
d/dr [r^8] = 8r^7
∫₀^∞ e^(-β²) dβ = √π / 2
257K
2β² + 4β + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
159K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
442K
det| 11 3 ; 0 12 | = 132
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
det| 9 4 ; 1 10 | = 86
22K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∫₀^∞ e^(-γ²) dγ = √π / 2
det| 3 4 ; 7 4 | = -16
\lim_{β\to 0} \frac{\sin β}{β} = 1