ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 20:26Z
5γ² + 3γ + 7 = 0
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
125K
8φ² + 2φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
det| 7 4 ; 4 8 | = 40
311K
det| 2 7 ; 7 3 | = -43
264K
det| 8 4 ; 6 9 | = 48
39K