ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:07Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
302K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
310K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\frac{11}{6} \sum_{i=1}^{n} i^{2}
264K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-t²) dt = √π / 2
39K
10r² + 7r + 5 = 0