ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 22:38Z
\frac{7}{5} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 9 4 ; 1 10 | = 86
312K
CaCO₃ → CaO + CO₂
8t² + 2t + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
17K
d/dφ [φ^12] = 12φ^11
E = mc²
∫₀^∞ e^(-x²) dx = √π / 2
10r² + 8r + 1 = 0