ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 21:44Z
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
259K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 7 8 ; 4 8 | = 24
159K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
270K
∇²t = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
231K
5ω² + 9ω + 6 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
202K