ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:29Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
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∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-r²) dr = √π / 2
12γ² + 2γ + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
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E = mc²
\oint_C \vec{F}\cdot d\vec{r} = 0
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λ = h/p
AgNO₃ + NaCl → AgCl↓ + NaNO₃
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∇ × E = −∂B/∂t