ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:49Z
10n² + 5n + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
302K
E = mc²
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
125K
det| 8 7 ; 7 9 | = 23
det| 3 7 ; 2 4 | = -2
310K
det| 7 4 ; 4 8 | = 40
311K
∫₀^∞ e^(-β²) dβ = √π / 2
264K