ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:04Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
302K
∫₀^∞ e^(-z²) dz = √π / 2
312K
4β² + 5β + 0 = 0
d/dφ [φ^6] = 6φ^5
6n² + 3n + 0 = 0
det| 10 9 ; 0 11 | = 110
311K
det| 1 4 ; 3 2 | = -10
39K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
364K