ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 21:23Z
e^{i\pi} + 1 = 0
d/dy [y^10] = 10y^9
∑_{k=1}^{n} k = n(n+1)/2
311K
det| 7 4 ; 4 8 | = 40
453K
det| 10 9 ; 3 11 | = 83
∫₀^∞ e^(-ω²) dω = √π / 2
133K
F = G m₁m₂ / r²
∫₀^∞ e^(-n²) dn = √π / 2
d/dt [t^6] = 6t^5
12r² + 1r + 3 = 0
5φ² + 5φ + 6 = 0
F = ma