ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:47Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∇²ω = 0
∫₀^∞ e^(-n²) dn = √π / 2
91K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
264K
2H₂ + O₂ → 2H₂O
det| 4 6 ; 0 5 | = 20
68K
10r² + 7r + 5 = 0
det| 5 6 ; 1 6 | = 24
364K
e^{i\pi} + 1 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
λ = h/p