ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:42Z
7φ² + 7φ + 6 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
125K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
91K
9n² + 8n + 4 = 0
\frac{11}{6} \sum_{i=1}^{n} i^{2}
310K
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
311K
E = mc²
∫₀^∞ e^(-β²) dβ = √π / 2
68K
CH₄ + 2O₂ → CO₂ + 2H₂O
39K