ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:11Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-ψ²) dψ = √π / 2
312K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
det| 9 2 ; 3 10 | = 84
311K
det| 9 4 ; 1 10 | = 86
264K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
68K
10r² + 7r + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
6K
AgNO₃ + NaCl → AgCl↓ + NaNO₃