ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:57Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-z²) dz = √π / 2
312K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
311K
det| 9 4 ; 1 10 | = 86
264K
det| 3 7 ; 2 4 | = -2
39K
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
364K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
6K