ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:22Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
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∫₀^∞ e^(-r²) dr = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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12γ² + 2γ + 2 = 0
E = mc²
λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
det| 7 4 ; 4 8 | = 40
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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