ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:14Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 1 ; 7 8 | = 49
302K
4β² + 5β + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
d/dφ [φ^6] = 6φ^5
6n² + 3n + 0 = 0
d/dz [z^11] = 11z^10
311K
det| 5 9 ; 7 6 | = -33
68K
∫₀^∞ e^(-θ²) dθ = √π / 2
39K