ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:43Z
10n² + 5n + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
312K
E = mc²
det| 7 7 ; 4 8 | = 28
125K
det| 9 4 ; 1 10 | = 86
91K
det| 8 7 ; 7 9 | = 23
det| 5 3 ; 2 6 | = 24
310K
∑_{k=1}^{n} k = n(n+1)/2
311K