ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:35Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
∫₀^∞ e^(-α²) dα = √π / 2
det| 7 4 ; 4 8 | = 40
453K
7y² + 6y + 1 = 0
E = mc²
AgNO₃ + NaCl → AgCl↓ + NaNO₃
45K
∇²y = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-β²) dβ = √π / 2