ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 17:27Z
∫₀^∞ e^(-φ²) dφ = √π / 2
rxn_4663.dat
∇²x = 0
259K
spec_4768.mol
∑_{k=1}^{n} k = n(n+1)/2
257K
det| 10 2 ; 5 11 | = 100
lat_3299.eqn
7γ² + 3γ + 1 = 0
159K
spec_6630.dat
det| 7 4 ; 4 8 | = 40
270K
PV = nRT
lat_3532.json
∫₀^∞ e^(-θ²) dθ = √π / 2
437K
mat_6103.dat
N₂ + 3H₂ ⇌ 2NH₃
442K
7y² + 8y + 2 = 0
ops_1628.mol
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
231K
spec_0034.csv
∂φ/∂ψ = 4φ
193K
eq_2085.eqn
3α² + 8α + 4 = 0
202K
eq_9380.mol
ΔS ≥ 0
22K
eq_9391.mol
e^{i\pi} + 1 = 0
479K
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Eq pack 25
Ledger /3
Matrix 29
Matrix 11
Rxn set 8
Rxn set 20
Batch 28
Batch 10
Rxn set 2
Σ#12
Σ#24
Batch 16
Eq pack 13
Rxn set 26
Eq pack 7