ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:55Z
7φ² + 7φ + 6 = 0
det| 9 4 ; 1 10 | = 86
302K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
125K
9n² + 8n + 4 = 0
ΔS ≥ 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
264K
E = mc²
\frac{8}{6} \sum_{i=1}^{n} i^{2}
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 5 ; 0 6 | = 30
det| 3 5 ; 7 4 | = -23
F = ma