ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 23:11Z
d/dr [r^8] = 8r^7
∫₀^∞ e^(-x²) dx = √π / 2
257K
2β² + 4β + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
270K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 3 1 ; 7 4 | = 5
231K
∫₀^∞ e^(-ω²) dω = √π / 2
202K