ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:33Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
∫₀^∞ e^(-ω²) dω = √π / 2
93K
∑_{k=1}^{n} k = n(n+1)/2
211K
∫₀^∞ e^(-α²) dα = √π / 2
\frac{4}{6} \sum_{i=1}^{n} i^{2}
453K
7y² + 6y + 1 = 0
\frac{2}{2} \sum_{i=1}^{n} i^{2}
133K
E = mc²
det| 9 4 ; 1 10 | = 86
207K
∇²y = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
333K
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-β²) dβ = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂