ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:26Z
10n² + 5n + 0 = 0
det| 9 2 ; 3 10 | = 84
312K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 8 7 ; 7 9 | = 23
det| 1 1 ; 5 2 | = -3
310K
d/dt [t^11] = 11t^10
CH₄ + 2O₂ → CO₂ + 2H₂O
311K
det| 7 4 ; 4 8 | = 40
39K