ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:17Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
∫₀^∞ e^(-α²) dα = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
311K
7y² + 6y + 1 = 0
\lim_{α\to 0} \frac{\sin α}{α} = 1
177K
E = mc²
det| 9 4 ; 1 10 | = 86
45K
det| 7 1 ; 7 8 | = 49
207K
∇²y = 0
∑_{k=1}^{n} k = n(n+1)/2
333K
\lim_{α\to 0} \frac{\sin α}{α} = 1
437K
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-β²) dβ = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂