ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:29Z
10n² + 5n + 0 = 0
∫₀^∞ e^(-t²) dt = √π / 2
312K
E = mc²
∫₀^∞ e^(-β²) dβ = √π / 2
125K
det| 5 9 ; 7 6 | = -33
91K
det| 8 7 ; 7 9 | = 23
det| 12 1 ; 5 13 | = 151
310K
d/dt [t^11] = 11t^10
det| 9 4 ; 1 10 | = 86
311K
∫₀^∞ e^(-y²) dy = √π / 2