ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 23:11Z
d/dr [r^8] = 8r^7
∫₀^∞ e^(-θ²) dθ = √π / 2
259K
2β² + 4β + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
270K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 11 3 ; 0 12 | = 132
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1