ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
312K
12φ² + 6φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
91K
2H₂ + O₂ → 2H₂O
det| 5 3 ; 7 6 | = 9
310K
CH₄ + 2O₂ → CO₂ + 2H₂O
311K
det| 9 4 ; 1 10 | = 86
39K