ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:38Z
N₂ + 3H₂ ⇌ 2NH₃
det| 9 4 ; 1 10 | = 86
302K
∑_{k=1}^{n} k = n(n+1)/2
312K
12φ² + 6φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-ω²) dω = √π / 2
17K
det| 3 1 ; 7 4 | = 5
310K
5φ² + 5φ + 0 = 0
det| 6 6 ; 3 7 | = 24
39K