ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:28Z
N₂ + 3H₂ ⇌ 2NH₃
12φ² + 6φ + 4 = 0
det| 12 1 ; 5 13 | = 151
125K
det| 9 2 ; 3 10 | = 84
91K
2H₂ + O₂ → 2H₂O
det| 7 4 ; 4 8 | = 40
17K
det| 3 1 ; 7 4 | = 5
310K
5φ² + 5φ + 0 = 0
\frac{6}{8} \sum_{i=1}^{n} i^{2}
det| 1 8 ; 4 2 | = -30
68K
ΔS ≥ 0
∫₀^∞ e^(-β²) dβ = √π / 2