ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-18 17:21Z
∫₀^∞ e^(-φ²) dφ = √π / 2
det| 11 5 ; 0 12 | = 132
259K
CH₄ + 2O₂ → CO₂ + 2H₂O
257K
det| 10 2 ; 5 11 | = 100
det| 9 4 ; 1 10 | = 86
159K
∑_{k=1}^{n} k = n(n+1)/2
270K
PV = nRT
7y² + 8y + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
231K
d/dz [z^11] = 11z^10
202K