ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-17 23:32Z
\lim_{β\to 0} \frac{\sin β}{β} = 1
det| 7 4 ; 4 8 | = 40
93K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
211K
∫₀^∞ e^(-α²) dα = √π / 2
det| 9 8 ; 3 10 | = 66
453K
7y² + 6y + 1 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
133K
E = mc²
det| 11 5 ; 0 12 | = 132
45K
∑_{k=1}^{n} k = n(n+1)/2
207K
∇²y = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
6r² + 8r + 4 = 0
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
∫₀^∞ e^(-β²) dβ = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂