ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 01:51Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 1 4 ; 3 2 | = -10
312K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
17K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
∑_{k=1}^{n} k = n(n+1)/2
311K
det| 12 9 ; 5 13 | = 111
264K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
39K