ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 16:49Z
10n² + 5n + 0 = 0
det| 10 4 ; 1 11 | = 106
302K
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
91K
det| 8 7 ; 7 9 | = 23
d/dt [t^11] = 11t^10
det| 1 4 ; 3 2 | = -10
311K
det| 4 6 ; 0 5 | = 20
264K
∫₀^∞ e^(-y²) dy = √π / 2