ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:31Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∫₀^∞ e^(-r²) dr = √π / 2
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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12γ² + 2γ + 2 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\frac{2}{2} \sum_{i=1}^{n} i^{2}
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E = mc²
det| 6 6 ; 3 7 | = 24
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det| 7 4 ; 4 8 | = 40
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λ = h/p