ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 18:13Z
∑_{k=1}^{n} k = n(n+1)/2
4β² + 5β + 0 = 0
det| 11 9 ; 0 12 | = 132
91K
d/dφ [φ^6] = 6φ^5
det| 3 6 ; 0 4 | = 12
310K
6n² + 3n + 0 = 0
det| 1 8 ; 4 2 | = -30
264K
det| 9 4 ; 1 10 | = 86
364K