ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:23Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-β²) dβ = √π / 2
302K
det| 6 6 ; 3 7 | = 24
312K
∫₀^∞ e^(-r²) dr = √π / 2
∫₀^∞ e^(-x²) dx = √π / 2
91K
12γ² + 2γ + 2 = 0
E = mc²
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
68K
\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}