ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 21:42Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∑_{k=1}^{n} k = n(n+1)/2
302K
det| 9 4 ; 1 10 | = 86
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∫₀^∞ e^(-r²) dr = √π / 2
det| 12 9 ; 5 13 | = 111
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12γ² + 2γ + 2 = 0
det| 9 8 ; 3 10 | = 66
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E = mc²
det| 1 1 ; 5 2 | = -3
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λ = h/p
det| 1 8 ; 4 2 | = -30
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\frac{3}{8} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}