ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 04:27Z
N₂ + 3H₂ ⇌ 2NH₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
302K
det| 9 4 ; 1 10 | = 86
312K
12φ² + 6φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
125K
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1
91K
2H₂ + O₂ → 2H₂O
det| 9 7 ; 3 10 | = 69
310K
5φ² + 5φ + 0 = 0
det| 10 1 ; 6 11 | = 104
264K
\frac{6}{8} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
39K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
6K