ChemCalc Dump /sym/93428e
id=1 · host=br.gridbatch.net · 2026-10-19 17:55Z
7φ² + 7φ + 6 = 0
det| 11 2 ; 5 12 | = 122
312K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
125K
9n² + 8n + 4 = 0
ΔS ≥ 0
\lim_{y\to 0} \frac{\sin y}{y} = 1
311K
E = mc²
det| 5 2 ; 3 6 | = 24
68K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 5 5 ; 0 6 | = 30